3x^2-1x-6=0

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Solution for 3x^2-1x-6=0 equation: 



3x^2-1x-6=0

a = 3; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·3·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*3}=\frac{1-\sqrt{73}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*3}=\frac{1+\sqrt{73}}{6}
$

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